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@@ -250,6 +250,19 @@ According to the LTE spec, the first OFDM symbol should use the long cyclic pref
 
 So, lets check to see if this math works out.  From the MATLAB plot earlier the OFDM symbol seemed to end (far right of the white box) around sample number `9,760`.  Assuming that each symbol after the first is `2048 + 144` or `2192` samples, the end of the previous OFDM symbol should be `9760 - 2192` or `7,568`
 
-![Screenshot from 2022-04-12 22-35-22](https://user-images.githubusercontent.com/4240543/163088581-9057c90a-8254-4b88-a12d-b22b2b2ef08d.png)
+![image](https://user-images.githubusercontent.com/4240543/163088695-9665d928-1fc7-471f-a7f0-45e0423b6e5c.png)
+
+The mouse cursor is roughly at `7,568` and that does look like the very beginning of the OFDM symbol from earlier.  Subtracting `2,192` again gives `5,376`
+
+![image](https://user-images.githubusercontent.com/4240543/163088951-f9382be1-d93b-4bf2-b0fc-1fbf47403806.png)
+
+Moving back again by `2,192` gives `3,184`
+
+![image](https://user-images.githubusercontent.com/4240543/163089050-a253c005-717e-46d7-abab-aa410e177093.png)
+
+For the next symbol the cyclic prefix length should be 160, so we need to subtract `2048 + 160` or `2208` which gives `3184 - 2208` or `976`
+
+![image](https://user-images.githubusercontent.com/4240543/163089256-8a6ebdf9-6ee9-4665-8b68-b8213c91ca6e.png)
+
+And that brings us back to the very beginning of the burst!  We can assume that a rough starting sample for the burst is `976`.  We will have to refine this value further in order to demodulate, but it's a starting point, and validates the expected cyclic prefix and FFT size assumptions.
 
-The