sane-project-website/old-archive/1997-08/0119.html

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<title>sane-devel: Re: umax-backend</title>
<h1>Re: umax-backend</h1>
<b>Jonathan A. Buzzard</b> (<a href="mailto:jab@hex.prestel.co.uk"><i>jab@hex.prestel.co.uk</i></a>)<br>
<i>Mon, 01 Sep 1997 13:45:46 +0100</i>
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<a href="mailto:R.E.Wolff@BitWizard.nl">R.E.Wolff@BitWizard.nl</a> said:<br>
<i>&gt; Yes, the q/a program will show "only noise" still, the doctors won't </i><br>
<i>&gt; allow you to trhow away that information. Maybe if you average 4 </i><br>
<i>&gt; pixels together that you get a little information. This IS visible to </i><br>
<i>&gt; the naked eye..... </i><br>
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Never said the radiologist would let you throw the info away, but noise<br>
is noise and averaging bits together will (should)<br>
<p>
<i>&gt; How do you measure the "just noise" in a 12bit scanner? I'd try to </i><br>
<i>&gt; generate a perfect analog greyscale and scan that.</i><br>
<p>
Not that I was involved in the q/a program, (it was an M.Sc. project done<br>
at the same time as mime, and I had to use the same scanner for some<br>
radiotherapy films). Roughly their was a test film which had a large number<br>
of squares of different (but uniform) optical density. Roughly a scan was<br>
taken of the film, a template was placed over the image and some statistics<br>
where done on the pixels of the different areas. As far as I understood<br>
the analysis showed that on a uniform area the distribution of the values<br>
in the lower two bits was more or less uniform. The conclusions drawn from<br>
that it must be noise.<br>
<p>
<p>
JAB.<br>
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Jonathan A. Buzzard,
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<li> <b>Next message:</b> <a href="0120.html">Oliver.Rauch@Wolfsburg.DE: "umax-backend"</a>
<li> <b>Previous message:</b> <a href="0118.html">Rogier Wolff: "Re: Backtracking in color scanning"</a>
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<li> <b>Next in thread:</b> <a href="0121.html">Rogier Wolff: "Re: umax-backend"</a>
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