kopia lustrzana https://github.com/micropython/micropython
17 wiersze
469 B
Python
17 wiersze
469 B
Python
"""
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categories: Core,Runtime
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description: Code running in eval() function doesn't have access to local variables
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cause: MicroPython doesn't maintain symbolic local environment, it is optimized to an array of slots. Thus, local variables can't be accessed by a name. Effectively, ``eval(expr)`` in MicroPython is equivalent to ``eval(expr, globals(), globals())``.
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workaround: Unknown
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"""
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val = 1
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def test():
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val = 2
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print(val)
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eval("print(val)")
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test()
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