py/parse: Treat constants that start with underscore as private.

Assignments of the form "_id = const(value)" are treated as private
(following a similar CPython convention) and code is no longer emitted
for the assignment to a global variable.

See issue #2111.
pull/2168/head
Damien George 2016-06-06 17:28:32 +01:00
rodzic 2bf6eb9fe2
commit b1533c4366
3 zmienionych plików z 26 dodań i 0 usunięć

Wyświetl plik

@ -461,6 +461,8 @@ STATIC const mp_rom_map_elem_t mp_constants_table[] = {
STATIC MP_DEFINE_CONST_MAP(mp_constants_map, mp_constants_table);
#endif
STATIC void push_result_rule(parser_t *parser, size_t src_line, const rule_t *rule, size_t num_args);
#if MICROPY_COMP_CONST_FOLDING
STATIC bool fold_constants(parser_t *parser, const rule_t *rule, size_t num_args) {
// this code does folding of arbitrary integer expressions, eg 1 + 2 * 3 + 4
@ -587,6 +589,15 @@ STATIC bool fold_constants(parser_t *parser, const rule_t *rule, size_t num_args
assert(elem->value == MP_OBJ_NULL);
elem->value = MP_OBJ_NEW_SMALL_INT(value);
// If the constant starts with an underscore then treat it as a private
// variable and don't emit any code to store the value to the id.
if (qstr_str(id)[0] == '_') {
pop_result(parser); // pop const(value)
pop_result(parser); // pop id
push_result_rule(parser, 0, rules[RULE_pass_stmt], 0); // replace with "pass"
return true;
}
// replace const(value) with value
pop_result(parser);
push_result_node(parser, pn_value);

Wyświetl plik

@ -9,3 +9,15 @@ def f():
print(X, Y + 1)
f()
_X = const(12)
_Y = const(_X + 34)
print(_X, _Y)
class A:
Z = const(1)
_Z = const(2)
print(Z, _Z)
print(hasattr(A, 'Z'), hasattr(A, '_Z'))

Wyświetl plik

@ -1,2 +1,5 @@
123 580
123 580
12 46
1 2
True False