py/emitnative: Fix x86-64 emitter to generate correct 8/16-bit stores.

Fixes issue #6643.

Signed-off-by: Damien George <damien@micropython.org>
pull/6646/head
Damien George 2020-11-24 23:37:58 +11:00
rodzic f49d47c167
commit 5176a2d732
3 zmienionych plików z 24 dodań i 2 usunięć

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@ -1769,7 +1769,7 @@ STATIC void emit_native_store_subscr(emit_t *emit) {
int reg_index = REG_ARG_2;
int reg_value = REG_ARG_3;
emit_pre_pop_reg_flexible(emit, &vtype_base, &reg_base, reg_index, reg_value);
#if N_X86
#if N_X64 || N_X86
// special case: x86 needs byte stores to be from lower 4 regs (REG_ARG_3 is EDX)
emit_pre_pop_reg(emit, &vtype_value, reg_value);
#else
@ -1856,7 +1856,7 @@ STATIC void emit_native_store_subscr(emit_t *emit) {
EMIT_NATIVE_VIPER_TYPE_ERROR(emit,
MP_ERROR_TEXT("can't store with '%q' index"), vtype_to_qstr(vtype_index));
}
#if N_X86
#if N_X64 || N_X86
// special case: x86 needs byte stores to be from lower 4 regs (REG_ARG_3 is EDX)
emit_pre_pop_reg(emit, &vtype_value, reg_value);
#else

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@ -0,0 +1,21 @@
# Miscellaneous viper tests
# Test correct use of registers in load and store
@micropython.viper
def expand(dest: ptr8, source: ptr8, length: int):
n = 0
for x in range(0, length, 2):
c = source[x]
d = source[x + 1]
dest[n] = (c & 0xE0) | ((c & 0x1C) >> 1)
n += 1
dest[n] = ((c & 3) << 6) | ((d & 0xE0) >> 4)
n += 1
dest[n] = ((d & 0x1C) << 3) | ((d & 3) << 2)
n += 1
source = b"\xaa\xaa\xff\xff"
dest = bytearray(len(source) // 2 * 3)
expand(dest, source, len(source))
print(dest)

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@ -0,0 +1 @@
bytearray(b'\xa4\x8aH\xee\xce\xec')