# Source: https://github.com/python/pyperformance
# License: MIT

# Simple, brute-force N-Queens solver.
# author: collinwinter@google.com (Collin Winter)
# n_queens function: Copyright 2009 Raymond Hettinger

# Pure-Python implementation of itertools.permutations().
def permutations(iterable, r=None):
    """permutations(range(3), 2) --> (0,1) (0,2) (1,0) (1,2) (2,0) (2,1)"""
    pool = tuple(iterable)
    n = len(pool)
    if r is None:
        r = n
    indices = list(range(n))
    cycles = list(range(n - r + 1, n + 1))[::-1]
    yield tuple(pool[i] for i in indices[:r])
    while n:
        for i in reversed(range(r)):
            cycles[i] -= 1
            if cycles[i] == 0:
                indices[i:] = indices[i + 1:] + indices[i:i + 1]
                cycles[i] = n - i
            else:
                j = cycles[i]
                indices[i], indices[-j] = indices[-j], indices[i]
                yield tuple(pool[i] for i in indices[:r])
                break
        else:
            return

# From http://code.activestate.com/recipes/576647/
def n_queens(queen_count):
    """N-Queens solver.
    Args: queen_count: the number of queens to solve for, same as board size.
    Yields: Solutions to the problem, each yielded value is a N-tuple.
    """
    cols = range(queen_count)
    for vec in permutations(cols):
        if (queen_count == len(set(vec[i] + i for i in cols))
                        == len(set(vec[i] - i for i in cols))):
            yield vec

###########################################################################
# Benchmark interface

bm_params = {
    (50, 25): (1, 5),
    (100, 25): (1, 6),
    (1000, 100): (1, 7),
    (5000, 100): (1, 8),
}

def bm_setup(params):
    res = None
    def run():
        nonlocal res
        for _ in range(params[0]):
            res = len(list(n_queens(params[1])))
    def result():
        return params[0] * 10 ** (params[1] - 3), res
    return run, result
